Question

Rohit purchased 12 shirts from a shopkeeper, each of rs. 400 1/30 and returned 6 trousers each of cost rs.500 1/8, find who is supposed to pay whom and how much

Chapter: Rational numbers, class 8
Kindly solve it correctly and properly with workings​

Answer 1

Answer:

Given:-

Rohit purchased 12 shirts from a shopkeeper, each of $₹400 \ \frac{1}{30}$ and returned 6 trousers each of cost $₹500 \ \frac{1}{8}$ , find who is supposed to pay whom and how much ?

To Find:-

Who is supposed to pay whom and how much

Note:-

●》First, we should find how shopkeeper gain money from rohit by making 1 shirts cost to 12 shirts and how much rohit gains from money shopkeeper by making 1 trouser cost to 6 trouser cost.

●》Mixed fraction should be changed to improper fraction during calculations.

●》Then we compare the value and the value which is greater, will be subtracted to the lower value.

Solution:-

[ First shopkeeper gains ]

Rohit purchased = 12 shirts

1 shirt = $₹400 \ \frac{1}{30}$, 12 shirts = ?

☆ According to note first, second point and we know that~

▪︎$1 shirt = ₹400 \ \frac{1}{30}$

▪︎$12 shirts = \frac{₹12,001}{30} × 12$

☆ After doing half calculations~

▪︎$12 shirts = \frac{₹12,001}{5} × 2$

☆ After doing whole calculations~

▪︎$12 shirts = \frac{₹24,002}{5}$

☆ Again the number will change to mixed fraction~

▪︎$12 shirts = ₹4800 \ \frac{2}{5}$

_______________________

[ Now, Rohit gains from shopkeeper ]

Returned trouser = 6

1 trouser = $₹500 \ \frac{1}{8}$ , 6 trouser = ?

☆ According to note first, second point and we know that~

▪︎$1 trouser = ₹500 \ \frac{1}{8}$

▪︎$6 trousers = \frac{₹4,001}{8} × 6$

☆ After doing calculations~

▪︎$6 trousers = \frac{₹12,003}{4}$

☆ Mixed fraction~

▪︎$6 trousers = ₹3000 \ \frac{3}{4}$

_____________________

[ Now, let's compare ]

☆ According to note third point~

▪︎$12 shirts ( shopkeeper ) \ \ □ \ \ 6 trousers ( Rohit )$

▪︎$₹4800 \ \frac{2}{5} \ \ □ \ \ ₹3000 \ \frac{3}{4}$

▪︎$\frac{₹24,002}{5} \ \ □ \ \ \frac{₹12,003}{4}$

☆ L.C.M is = 20

▪︎$\frac{₹24,002}{5} × \frac{4}{4} \ \ □ \ \ \frac{₹12,003}{4} × \frac{5}{5}$

▪︎$\frac{₹96,008}{20} \ \ > \ \ \frac{₹60,015}{20}$

So rohit is supposed to pay shopkeeper, by how much = ?, so~

▪︎$\frac{₹96,008}{20} - \frac{₹60,015}{20}$

▪︎$\frac{₹35,993}{20}$

☆ Mixed fraction and decimal~

▪︎$₹1,799 \ \frac{13}{20}$ and $₹1799.65$

Answer:-

Hence, Rohit is supposed to pay shopkeeper by $₹1,799 \ \frac{13}{20}$ or $₹1799.65$

:)