Math, asked by sneha0311, 10 months ago

Rohit secured 42% of the total marks and secured 10 marks more than the passing marks . In the same exam , Mohit scored 29% of the total marks and failed by 16 marks . What was the passing percentage?

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Answers

Answered by arghoa8
7

Answer:

The passing percentage was 37

Step-by-step explanation:

Let, total number was X

the passing number was Y

Rohit secured 42%

Rohit left 58%

He secured 10 marks more than Y.

Equation is X-(X×58/100) = Y+10

Like this the equation of Mohit is ,

X-(X×71/100)= Y-16

Solving this you will get X= 200

and Y= 74

so,the passing percentage was = 74×100/200=37%

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