Rohit sharma's score in a T20 game is 4 times the average of his in the previous 5 games. what has been the percentage increase in his average after the 6th game?
Answers
Answer:
50%
Step-by-step explanation:
score in 6th innings = X6 = 4×(X)
X = avg. in previous 5 games
% increase in his avg. =( (avg. of 6 innings) - ( avg. of 5 innings) ) / (avg. of 5 innings)
= ( (5/6)(X) + (4/6)(X) - (X) ) / ( X )
= 1/2
= 50%
Answer:
50%
Step-by-step explanation:
Let his score in this game be 'x'.
As given, 'x' is 4 times the average score in the previous 5 games.
∴ x = 4 * average score in the previous 5 games.
⇒ x/4 = average ...(1)
⇒ x/4 = (sum of last 5 matches)/5
⇒ 5x/4 = (sum of last 5 matches)
Now, sum of scores = x + 5x/4
= 9x/4
∴ New average = (9x/4) / 6
= 9x/24
∴ % increase in average =
= (9x/24 - x/4)/(x/4) * 100%
= (9/6 - 1)/1 * 100%
= 1/2 * 100%
= 50%
The percentage increase in his average after the 6th game is 50%