Question

Rohit sharma's score in a T20 game is 4 times the average of his in the previous 5 games. what has been the percentage increase in his average after the 6th game?

Answer 1

score in 6th innings = X6 = 4×(X)

X = avg. in previous 5 games

% increase in his avg. =( (avg. of 6 innings) - ( avg. of 5 innings) ) / (avg. of 5 innings)

= ( (5/6)(X) + (4/6)(X) - (X) ) / ( X )

= 1/2

= 50%

Answer 2

There is increment of 50% in his average score.

Step-by-step explanation:

Let the average of his score in the previous 5 games be 'x'.

Sum of his scores becomes $5x$

Now, his score is 4 times the average in the previous 5 games.

So, it becomes

$4x$

So, his average becomes,

$\dfrac{5x+4x}{6}=\dfrac{9x}{6}=1.5x$

So, percentage of increase in his average becomes

$\dfrac{1.5x-x}{x}\times 100\\\\=\dfrac{0.5}{1}\times 100\\\\=50\%$

Hence, there is increment of 50% in his average score.

# learn more:

A batman scores 80 runs in his 6th innings and thus increases his average by 5 find his average after 6 innings

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