ROHIT SOLD 2 MOBILE SET FOR ₹10000 each. on one he gained 10% and on another he losses 10%.how much he gained or lossed in whole transaction.find alsobthe profit or loss %
Answers
Answered by
0
Answer:
let x be cost of 1st phone and y be of 2nd
ATQ
x+y=10,000
and also
(110/100)×x=(90/100)×y
=> 11x=9y
=>11x-9y = 0
solving both the equation
we get x= 4,500
and y=5,500
Hope this helps you
MARK THIS ANSWER AS BRAINLIEST ANSWER
Answered by
3
let the two mobile's be x and y
x be sold at 10% gain
y be sold at 10% lost
x = (100+10) = 110%
y = (100-10) = 90%
cost price of x = 10000/110 = 90.90
cost price of y = 10000/90 = 111.11
Net loss = 111.11 - 90.90 = Rs.20.21
Similar questions