Math, asked by nazfarhu786, 10 months ago

ROHIT SOLD 2 MOBILE SET FOR ₹10000 each. on one he gained 10% and on another he losses 10%.how much he gained or lossed in whole transaction.find alsobthe profit or loss %​

Answers

Answered by yogiram12345
0

Answer:

let x be cost of 1st phone and y be of 2nd

ATQ

x+y=10,000

and also

(110/100)×x=(90/100)×y

=> 11x=9y

=>11x-9y = 0

solving both the equation

we get x= 4,500

and y=5,500

Hope this helps you

MARK THIS ANSWER AS BRAINLIEST ANSWER

Answered by krishnajana295
3

let the two mobile's be x and y

x be sold at 10% gain

y be sold at 10% lost

x = (100+10) = 110%

y = (100-10) = 90%

cost price of x = 10000/110 = 90.90

cost price of y = 10000/90 = 111.11

Net loss = 111.11 - 90.90 = Rs.20.21

Similar questions