Rohit swims in a 120m long pool. He covers 240m in 80 secs by swimming from one end to the other and back along the same straight path. Find the average speed and average velocity of Rohit.
Answers
Rohit swims in a 120 m long pool. (Length of pool = 120 m). He covers 240m in 80 secs by swimming from one end to the other and back along the same straight path.
We have to find the average speed and average velocity of Rohit.
Average speed is defined as the total distance covered with respect to total time taken. Whereas average velocity is defined as the ratio of total displacement with respect to the total time taken.
As given in question that, the Rohit covers a distance of 240 m in 80 sec.
(Total distance covered is 250 m and time taken is 80 sec).
Average speed = 240/80 = 3 m/s
Therefore, the average speed of the Rohit is 3 m/s.
Since, he is swimming from one end to the other and back along the same straight path. So, the total displacement of the Rohit is zero.
Therefore, the average velocity of the Rohit is 0 m/s.
Answer:
average speed =3m/s
average velocity=0
average speed = total distance/total time
=240m/80 sec
=3m/s
Displacement is the straight line distance between initial and the final position
His final and initial points are same
so displacement = 0
Average velocity = total displacement ÷ total time
=0m/80 sec
= 0
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