Question

Rokesh's age is less than Sania's age
by 6 years. The sum of their
ages
is 27
I years.
How old are they?​

Answer 1

Answer:

Sania's age = 16.05 years.

Rokesh's age = 11.05

Step-by-step explanation:

Given:

• Rokesh's age is less than Sania's age by 6 years.

• Sum of there age is 27 years.

To find:

• There real age = ?

Procedure:

Let's assume Sania's age = x years

It is said that Rokesh's age is less than Sania's age by 6 years.

So, Rokesh's age = x - 6

We know sum of their ages = 27.

So, Equation formed would be,

$\implies \sf \: (x) + (x - 6) = 27$

$\implies \sf \: 2x = 27 + 6$

$\implies \sf \: 2x = 33$

$\implies \sf \: x = \dfrac{33}{2}$

$\implies \sf \: x = 16.05$

Now,

Sania's age is 16.05 years.

Rokesh's age = x - 6 = 16.05 - 6

=> 11.05years.

Answer 2

Correct Question:-

Rokesh’s age is less than Sania’s age by 6 years. The sum of their ages is 27 years. How old are they?

Solution:-

$\boxed{\rm{\orange{Given \longrightarrow }}}$

• Rokesh's age is less than Sania's age by 6 years.

• Sum of the ages of Rokesh and Sania is 27 years.

$\boxed{\rm{\red{To\:Find\longrightarrow }}}$

• Their present Ages?

$\boxed{\rm{\pink{Explanation\longrightarrow }}}$

Let the age of Rokesh be x years.

So, Sania’s age = (x -6) years. 

According to the given condition, 

$\sf\blue{↬}$x + (x -6) = 27 

$\sf\purple{↬}$2x =27 + 6

$\sf\green{↬}$2x = 33

$\sf\pink{↬}$x= $\dfrac{33}{2}$= 16.05

Sania’s age = x + 5 = 11 + 5 = 16.05 years 

$\therefore$The ages of Rokesh and Sania are 11.05 years and 16.05 years respectively.