Question

Roll a biased die probability that even number appears is twice as that of odd number appears. let A be the event that a number less than 3 appears find probability of A

Answer 1

Answer:

Let probability of getting an even number = x

Let probability of getting odd number = y

3x+3y=1 (probability of getting even number or odd number = 1 since those two are the only possibilities)

x=2y (given)

Solving these two,

x=2/9 and y=1/9

Now, getting 11 in two rolls of dice is only possible in two ways.

Getting a 5 and 6, and getting a 6 and 5

Answer:

P(getting 5).P(getting 6) + P(getting 6).P(getting 5)

(1/9)∗(2/9)+(2/9)∗(1/9)

4/81