Roller 120 cm long has diameter 56cm to level a playground it takes 800 complete revolutions determine the cost of levelling the playground @ 60 per square metre
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curved surface area = 2×22/7× r×h
r=56/2
csa=2×22/7×56/2×120
=295680/14
=21120
= to complete 800 revolution
=21120×800
cost=21120×800/60
=21120×5
=rupees 105600
please mark it brainliest
r=56/2
csa=2×22/7×56/2×120
=295680/14
=21120
= to complete 800 revolution
=21120×800
cost=21120×800/60
=21120×5
=rupees 105600
please mark it brainliest
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