Math, asked by dineshkumr4242, 8 months ago

roman number 50- 101​

Answers

Answered by Anonymous
3

Answer:

CI = 100 + 1

102 = CII = 100 + 1 + 1

103 = CIII = 100 + 1 + 1 + 1

104 = CIV = 100 + 5 − 1

105 = CV = 100 + 5

106 = CVI = 100 + 5 + 1

107 = CVII = 100 + 5 + 1 + 1

108 = CVIII = 100 + 5 + 1 + 1 + 1

109 = CIX = 100 + 10 − 1

110 = CX = 100 + 10

111 = CXI = 100 + 10 + 1

112 = CXII = 100 + 10 + 1 + 1

113 = CXIII = 100 + 10 + 1 + 1 + 1

114 = CXIV = 100 + 10 + 5 − 1

115 = CXV = 100 + 10 + 5

116 = CXVI = 100 + 10 + 5 + 1

117 = CXVII = 100 + 10 + 5 + 1 + 1

118 = CXVIII = 100 + 10 + 5 + 1 + 1 + 1

119 = CXIX = 100 + 10 + 10 − 1

120 = CXX = 100 + 10 + 10

121 = CXXI = 100 + 10 + 10 + 1

122 = CXXII = 100 + 10 + 10 + 1 + 1

123 = CXXIII = 100 + 10 + 10 + 1 + 1 + 1

124 = CXXIV = 100 + 10 + 10 + 5 − 1

125 = CXXV = 100 + 10 + 10 + 5

126 = CXXVI = 100 + 10 + 10 + 5 + 1

127 = CXXVII = 100 + 10 + 10 + 5 + 1 + 1

128 = CXXVIII = 100 + 10 + 10 + 5 + 1 + 1 + 1

129 = CXXIX = 100 + 10 + 10 + 10 − 1

130 = CXXX = 100 + 10 + 10 + 10

131 = CXXXI = 100 + 10 + 10 + 10 + 1

132 = CXXXII = 100 + 10 + 10 + 10 + 1 + 1

133 = CXXXIII = 100 + 10 + 10 + 10 + 1 + 1 + 1

134 = CXXXIV = 100 + 10 + 10 + 10 + 5 − 1

135 = CXXXV = 100 + 10 + 10 + 10 + 5

136 = CXXXVI = 100 + 10 + 10 + 10 + 5 + 1

137 = CXXXVII = 100 + 10 + 10 + 10 + 5 + 1 + 1

138 = CXXXVIII = 100 + 10 + 10 + 10 + 5 + 1 + 1 + 1

139 = CXXXIX = 100 + 10 + 10 + 10 + 10 − 1

140 = CXL = 100 + 50 − 10

141 = CXLI = 100 + 50 − 10 + 1

142 = CXLII = 100 + 50 − 10 + 1 + 1

143 = CXLIII = 100 + 50 − 10 + 1 + 1 + 1

144 = CXLIV = 100 + 50 − 10 + 5 − 1

145 = CXLV = 100 + 50 − 10 + 5

146 = CXLVI = 100 + 50 − 10 + 5 + 1

147 = CXLVII = 100 + 50 − 10 + 5 + 1 + 1

148 = CXLVIII = 100 + 50 − 10 + 5 + 1 + 1 + 1

149 = CXLIX = 100 + 50 − 10 + 10 − 1

150 = CL = 100 + 50

151 = CLI = 100 + 50 + 1

152 = CLII = 100 + 50 + 1 + 1

153 = CLIII =

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