Question

Ronald , a woodworker, can complete building three chairs in seven days. How many chairs can he build in 35 days?

Answer 1

Given :-

• Ronald, a woodworker can complete three chairs in seven days.

To Find :-

• How many chairs can he build in 35 days ?

Solution :-

seven days = 1 week

Hence Ronald can complete three chairs in one week.

35 days = 5 weeks

Hence 3 × 35 = 105 chairs

So, the workers can complete 105 chairs in 35 days.

Answer 2

Answer:

Ronald would make 15 chairs in 35 days.

Step-by-step explanation:

We know that,

Ronald can finish 3 chairs in 7 days,

Now,

Let his work strength be proportional or consistent, that is, he does equal work in all days,

Thus,

The work done and number of days will be proportional,

Let Ronald make x chairs in 35 days

Hence,

3/7 = x/35

Cross multiplying we get

7x = 3 × 35

7x = 105

x = 105/7

x = 15

OR

3 : 7 :: x : 35

We know that,

Product of extremes = Product of means

3 × 35 = 7x

105 = 7x

x = 105/7

x = 15

Thus,

Ronald would make 15 chairs in 35 days.

Hope it helped and believing you understood it........All the best.