Math, asked by cbsetopper2145, 5 days ago

Ronit and Nilesh invested a total of 130000 rupees in a business in the proportion of 3 : 2 respectively. what amount did each of them invested?

Answers

Answered by bagkakali
0

Answer:

Ronit invested Rs 130000×3/5

=Rs 26000×3

=Rs 78,000

Nilesh invested Rs 130000×2/5

Rs 26,000×2

=Rs 52,000

Answered by kadeejasana2543
0

Answer:

Ronit invested 78000 rupees  and  Nilesh invested 52000 rupees.

Step-by-step explanation:

Given Ronit and Nilesh invested 130000 rupees in the ratio 3:2.

One way to find the amount of each partner is:

Ronit invested 3x rupees and

Nilesh invested 2x rupees.

and the total 5x=130000, therefore  x=130000/5=26000.

Therefore share of Ronit =3*26000=78000 rupees

and share of Nilesh =2*26000=52000 rupees.

An other way is ,

Share of Ronit =130000*\frac{3}{5} =26000*3=78000 rupees

and share of Nilesh =130000*\frac{2}{5} =26000*2=52000 rupees

Hence the answer

thank you

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