Question

Ronny and Mark have X and Y number of sweets. X and Y are such that the sum of 5% of Xand 4% of
Y is two-third of the sum of 6% of X and 8% of Y. Find the ratio of sweets with Ronny and Mark.​

Answer 1

Answer:

5%x +4%y =2/3 (6%x +8%y)

15%x +12%y = 12%x +16% y

3%x = 4%y

x : y =4:3

Step-by-step explanation:

Answer 2

Given:

Ronny and Mark have X and Y numbers of sweets. X and Y are such that the sum of 5% of X and 4% of Y is two-thirds of the sum of 6% of X and 8% of Y.

To find:

The ratio of sweets with Ronny and Mark.

Solution:

To determine the ratio of sweets with Rony and Mark we have to follow the below steps as follows-

Ronny and Mark have X and Y numbers of sweets.

A sum of 5% of X and 4% of Y is given as

$\frac{5}{100} x + \frac{4}{100}y$

The sum of 6% of X and 8% of Y is given as-

$\frac{6}{100} x + \frac{8}{100} y$

The sum of 5% of X and 4% of Y is two-thirds of the sum of 6% of X and 8% of Y.

So, we can write-

$\frac{5}{100} x + \frac{4}{100}y = \frac{2}{3} \times ( \frac{6}{100} x + \frac{8}{100}y ) \\( 5x + 4y) \times 3 =( 6x + 8y) \times 2 \\ 15x + 12y = 12x + 16y \\ 3x = 4y \\ \frac{x}{y} = \frac{4}{ 3}$

The ratio of sweets with Ronny and Mark is 4:3.