Question

Roohi travels 300 km to her home partly by train and partly by bus. She takes 4
boars if she travels 60 km by train and the remaining by bus. If she travels 100 km
by train and the remaining by bus, she takes 10 minutes longer. Find the speed of
the train and the bus separately.​

Answer 1

Answer:

let the speed of the train be x km/h

let the speed of bus be y km/h

60/x + 240/y = 4

100/x + 200/y = 4+10/60

100 x + 200 y = 25/6

let 1/x be a

let 1/y be. b

60a + 240b = 4. eq 1.

100 a + 200 b = 25/6

600 a + 1200 b = 25. eq 2

×10 in eq 1. 600a + 2400 b = 40

600 a + 1200 b = 25

1200b = 15

b = 15/1200

b = 1/80

put b= 1/89in eq 2 .

a= 1/60

so x=60

y=80

speed of train is 60km/h

speed of bus is 80km/h

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Answer 2

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Let the speed of train and bus be u km/h and v km/h respectively.

According to the question,

$\frac{60}{u} + \frac{240}{v} = 4$....(i)

$\frac{100}{u} + \frac{200}{v} = 4 + \frac{10}{60} = \frac{25}{6}$....(ii)

Let $\frac{1}{u} = p\: and \frac{1}{v} = q$

The given equations reduce to:

60p + 240q = 4 ....(iii)

100p + 200q = $\frac{25}{6}$

600p + 1200q = 25....(iv)

Multiplying equation (iii) by 10, we obtain:

600p + 2400q = 40....(v)

Subtracting equation (iv) from equation (v), we obtain:

1200q = 15

q = $\frac{15}{1200} = \frac{1}{80}$

Substituting the value of q in equation (iii), we obtain:

60p + 3 = 4

60p = 1

p = $\frac{1}{60}$

:. p = $\frac{1}{u} = \frac{1}{60}$, q = $\frac{1}{v} = \frac{1}{80}$

u = 60 km/h , v = 80 km/h

Thus, the speed of train and the speed of bus are 60 km/h and 80 km/h respectively.

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