Question

Roohi travels 300 km to her home partly by train and partly by bus. She takes 4
hours if she travels 60 km by train and the remaining by bus. If she travels 100 km
by train and the remaining by bus, she takes 10 minutes longer. Find the speed of
the train and the bus separately.
​

Answer 1

Answer:

Answer:

Solution:-

Let the speed of train and bus be u km/h and v km/h.        

       

According to the question:

60/u + 240/v = 4 ... (i)  

100/u + 200/v = 25/6 ... (ii)    

Putting 1/u = p and 1/v = q in the equations, we get    

⇒ 60p + 240q = 4 ... (iii)                  

⇒ 100p + 200q = 25/6                  

⇒ 600p + 1200q = 25 ... (iv)  

Multiplying equation (iii) by 10, we get  

               

⇒ 600p + 2400q = 40 .... (v)  

               

Subtracting equation (iv) from (v), we get 1200q = 15                  

⇒ q = 15/200 = 1/80 ... (vi)    

             

Putting equation (iii), we get    

             

⇒ 60p + 3 = 4                  

⇒ 60p = 1                  

⇒ p = 1/60                  

⇒ p = 1/u = 1/60 and q = 1/v = 1/80                  

⇒ u = 60 and v = 80    

             

Speed of train = 60 km/h  

Speed of bus = 80 km/h.Answer Expert Verified

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Hi ,

Dimensions of the cuboidal fish tank :

length = l = 1 m = 100 cm

breadth = b = 40 cm

height = h = 50 cm

Volume of the tank ( V ) = lbh

V = 100 cm × 40cm × 50 cm

V = 200000 cm³

V = 200000 × 1/1000 litres

V = 200 litres

Therefore ,

Capacity of the water tank = 200 litres

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Answer 2

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Let the speed of train and bus be u km/h and v km/h respectively.

According to the question,

$\frac{60}{u} + \frac{240}{v} = 4$....(i)

$\frac{100}{u} + \frac{200}{v} = 4 + \frac{10}{60} = \frac{25}{6}$....(ii)

Let $\frac{1}{u} = p\: and \frac{1}{v} = q$

The given equations reduce to:

60p + 240q = 4 ....(iii)

100p + 200q = $\frac{25}{6}$

600p + 1200q = 25....(iv)

Multiplying equation (iii) by 10, we obtain:

600p + 2400q = 40....(v)

Subtracting equation (iv) from equation (v), we obtain:

1200q = 15

q = $\frac{15}{1200} = \frac{1}{80}$

Substituting the value of q in equation (iii), we obtain:

60p + 3 = 4

60p = 1

p = $\frac{1}{60}$

:. p = $\frac{1}{u} = \frac{1}{60}$, q = $\frac{1}{v} = \frac{1}{80}$

u = 60 km/h , v = 80 km/h

Thus, the speed of train and the speed of bus are 60 km/h and 80 km/h respectively.

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