Question

Roohi travels 300 km to her home partly by train and partly by bus. She takes 4 hours if she travels 60 km by train and the remaining by bus. If she travels 100 km by train and the remaining by bus, she takes 10 minutes longer. Find the speed of the train and the bus separately solve in elimination method

Answer 1

${Answer :-}$

Let, the speed of the bus be x.
And speed of train be y.

Now, we have 4 hours = 240 mins.

Now, 60/y + 240/x = 240.
Or, ( 60x + 240y) /xy = 240.
Or, 60( x + 4y) = 60 * 4 * xy.
Or, x + 4y = 4xy................... (1)

Again, we have that,
As, 100/y + 200x = 250.
Or, ( 100x + 200y) /xy = 250.
Or, 50 ( 2x + 4y) = 50 * 5 * xy.
Or, 2x + 4y = 5xy....................... (2)

Now, (2) - (1),we get.
2x + 4y - x - 4y = 5xy - 4xy.
Or, x = xy.
Or, y = 1.

Now, x + 4(1) = 4(1)x
Or, x + 4 = 4x.
Or, x = 4/3.

Thus, the speed of the bus is 4/3 km/min = (4/3 * 60) km/h = 80 km/h.
And, speed of the train is 1 km/min = (1 * 60)km/h = 60 km/h.

Thus, speed of bus = 80 km/h.
Speed of train = 60 km/h.

Hope this helps,.

If helps, please mark it as brainliest ^_^

Answer 2

Answer:

Hope it helps.....

Thank you