Question

Room 5m 55cm long and 3m 74 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.

Answer 1

Step-by-step explanation:

Area of room=side×side

=555cm×555cm

=308025cm

Area of tiles=374cm ×374cm

=139876cm

Tiles required=308025÷139876

Answer 2

Complete Question:

Room 5m 44cm long and 3m 74 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.

Answer:

The least number of square tiles required to cover the floor is 176

Solution:

Room 5m 44cm long and 3m 74 cm broad

We know that,

1 m = 100 cm

Therefore,

length = 5 m 44 cm = 544 cm

breadth = 3 m 74 cm = 374 cm

Area of room = 544 x 374

Therefore,

Size of square tile = GCF of 544 and 374

Size of square tile = 34

Therefore,

$\text{Area of largest square tile } = 34^2 = 1156$

Find the least number of square tiles required to cover the floor

$\text{Number of square tiles } = \frac{ \text{ area of room }}{ \text{ area of largest square tile }}\\\\\text{Number of square tiles } = \frac{ 544 \times 374 }{1156}\\\\\text{Number of square tiles } =176$

Thus the least number of square tiles required to cover the floor is 176

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