Math, asked by sajiya95, 2 months ago

room is 15 metre long and 8th floor is to be covered with rectangular tiles each measuring 25 CM by 87 how many times with be required​

Answers

Answered by reddysaritham
0

Step-by-step explanation:

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We know, 50cm=0.5m and 

25cm=0.25m

Tiles along the length of the room=0.515 = 30 tiles

Tiles along the length of the room=0.258 =32 tiles

Total number of tiles required =30×32 =960 tiles

To leave 1m between the carpet and wall on all sides, the carpet needs to be 2m shorter in each dimension.

Therefore,

  (15−2)m(8−2)m

=(13×6)m

=78m2

Therefore, the room area is 15×8 = 120m2

The carpet area is 78m2

The fraction of the area uncovered =120120−78= 12042=207

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