Question

room is 6m long, 5.2m broad and 4.5m high. It has two doors each
of 1.2m by 2m and three windows each of 1m by 80cm. Find cost of
distempering the walls of the room from inside at the rate of Rs.6 per m

Answer 1

Answer:

Length of the room = 5 m

Breadth of the room = 4.5 m

Height of the room = 3.6 m

Area of the roof = L × B

= 5 × 4.5 m2

= 22.5 m2

Area of four walls = 2[L + B] × H

= 2[5 + 4.5] × 3.6

= 2(9.5) × 3.6

= 19 × 3.6

= 68.4 m2

Area of one door = 1.5 × 2.4 m2

= 3.60 m2

= 3.6 m2

= 68.4 m2

Area of one window = 1 × 0.75 m2

= 0.75 m2

Area of 2 windows = 0.75 × 2 m2

= 1.5 m2

(i) Area of four walls excluding door and windows

= 68.4 – (3.6 + 1.5)

= 68.4 – 5.1

= 63.3 m2

(ii) Cost of distempering four walls @ Rs. 4.50 per m2

= 63.3 × 4.50

= Rs. 284.85

(iii) Cost of painting the roof @ Rs. 9 per m2

= 22.5 × 9

= Rs. 202 .50

Answer 2

Step-by-step explanation:

area of room = 6*5.2*4.5= 140.4

Area of 1 door = 1.2*2= 2.4

Area of 2 door = 2.4*2= 4.8

Area of 3 window= 1*0.8*3= 2.4

Area for distempering= 140.4-4.8-2.4=133.2m^2

Rate =133.2*6= 799.20Rs