Question

root 1- cos thita ÷1+ cos thita = sin thita / 1 + cos thita for thita = 60

Answer 1

From L.H.S

$= \sqrt{ \frac{1 - \cos( \alpha ) }{1 + \cos( \alpha ) } } \\ \\ = \sqrt{ \frac{(1 - \cos( \alpha )) \times (1 + \cos( \alpha ) ) }{(1 + \cos( \alpha ) ) \times (1 + \cos( \alpha )) } } \\ \\ = \sqrt{ \frac{1 - \cos {}^{2} ( \alpha ) }{(1 + \cos( \alpha ) ) {}^{2} } } \\ \\ = \sqrt{ \frac{ \sin {}^{2} ( \alpha ) }{(1 + \cos( \alpha ) ) {}^{2} } } \\ \\ = \frac{ \sin( \alpha ) }{1 + \cos( \alpha ) }$

= R. H. S.

proved

hope it helps....