[root(-1)]^n pls answer it
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√-1^n
∵ we know that 1 raised to any power equals 1.
=√-1
∵ we know that the square root of a negative number doesn't existin the set of real numbers.
=√-1
Please mark my answer as brainliest.
∵ we know that 1 raised to any power equals 1.
=√-1
∵ we know that the square root of a negative number doesn't existin the set of real numbers.
=√-1
Please mark my answer as brainliest.
mkc708:
it's right
tell
post your answer
hey, {√(-1)}^n = ¡ ^n ; as we know i^2 = -1 and i^4 = 1 , so to find i^n (devide n by 4 ) , let q be the quotient and r be the remender , n = 4q + r , hence i^(4q+r) = (i^4)^q × i^r = 1 × i^r = i^r , here r can be 1,2 or 3, then i^1 = i , i^2 = -1, i^3 = -i
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