root 1+sin 2 theta =cos theta +sin theta
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using formula of sin 2 theta
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how did u take that sin square theta +cos square theta
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√1+sin2A
=1+sin2A
=sin²A+cos²A+2sinA.cosA
=(sinA+cosA)²
=1+sin2A
=sin²A+cos²A+2sinA.cosA
=(sinA+cosA)²
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