root 1 + sin a upon under root 1 minus sin a is equal to Cos A upon 1 minus sin a
please mates its urgent please help me please :( :-(
Answers
Answered by
25
Taking LHS
√1+sinA/√1-sinA = cosA/1-sinA
Rationalising,
=√1+sinA/√1-sinA * √1+sinA/√1+sinA
=(√1+sinA)^2/√1-sin^2A
=(√1+sinA)^2/cos^2A {sin^2A +cos^2A}
=(√1+sinA/cosA)^2
=1+sinA/cosA
Hence, LHS=RHS
1+sinA/cosA=1+sinA/cosA
√1+sinA/√1-sinA = cosA/1-sinA
Rationalising,
=√1+sinA/√1-sinA * √1+sinA/√1+sinA
=(√1+sinA)^2/√1-sin^2A
=(√1+sinA)^2/cos^2A {sin^2A +cos^2A}
=(√1+sinA/cosA)^2
=1+sinA/cosA
Hence, LHS=RHS
1+sinA/cosA=1+sinA/cosA
yuvikacool123:
i don't like
you don't like what??
oh! i am sorry i took it another ques
this answer is wrong.
your presentation of this question solution
cheat from Google cheater:-)
:-DD
i'll tell you later
i didn't cheat
this ques was also present in my own book that's why i didn't pay much attention to this one.
Answered by
0
Step-by-step explanation:
- hope you understand
- freefire user I'd - Capitanfox00
Attachments:
Similar questions