Root 1+sin theta/1-sin theta = cos theta/1-sin theta
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Answer:
√1−sinθ1+sinθ
=√1−sinθ1+sinθ⋅1−sinθ1−sinθ
=√(1−sinθ)21−sin2θ
=√(1−sinθ)2cos2θ
=√∣1−sinθcosθ∣
=√1−sinθ|cosθ|
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