Math, asked by vikrantgslv3, 1 month ago

root(1+sinA/1-sinA)+root(1-sinA/1+sinA)​

Answers

Answered by abhisharma9084414167
0

Answer:

Solution:

LHS = \sqrt{(\frac{1+sinA}{1-sinA})}+\sqrt{(\frac{1-sinA}{1+sinA})}

(

1−sinA

1+sinA

)

+

(

1+sinA

1−sinA

)

= \frac{\sqrt{(1+sinA)^{2}}+\sqrt{(1-sinA)^{2}}}{\sqrt{(1-sinA)}\cdot\sqrt{(1+sinA)}}

(1−sinA)

(1+sinA)

(1+sinA)

2

+

(1−sinA)

2

= frac{1+sinA+1-sinA}{\sqrt{1-sin^{2}A}}frac1+sinA+1−sinA

1−sin

2

A

= \frac{2}{\sqrt{cos^{2}A}}

cos

2

A

2

= \frac{2}{cosA}

cosA

2

= 2secA2secA

= RHS

••••

Answered by GraceS
2

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HERE IS UR ANSWER

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