Question

Root 1-sintheata/1+sintheata=sectheata-tantheata

Answer 1

Hi ,

I'm using x instead of theta.

LHS = √(1 - sinx )/ √( 1 + sinx )

= √( 1 - sinx )² / √(1 + sinx )( 1 - sinx )

= √ ( 1 - sinx )² / √ [ 1² - sin² x ]

= √ ( 1 - sinx )² / √cos² x

= ( 1 - sinx ) / cosx

= 1/ cosx - sinx / cosx

= Secx - tanx

= RHS

I hope this helps you.

:)