Math, asked by jayesh55, 1 year ago

root 11 minus root 7 upon root 11 + root 7

Answers

Answered by OS13
10
Hey!!!
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●I think its rationalisation
 \frac{ \sqrt{11 - \sqrt{7} } }{ \sqrt{11} + \sqrt{7} }
Rationalising the denominator
We get, \frac{ \sqrt{11 }- \sqrt{7} }{ \sqrt{11} + \sqrt{7} } \times \frac{ \sqrt{11 }- \sqrt{7} }{ \sqrt{11} - \sqrt{7} } \\ \frac{{ {( \sqrt{11} - \sqrt{7} )}^{2} }}{ ({ \sqrt{11} )}^{2} - ( { \sqrt{7}) }^{2} } \\ \frac{ { \sqrt{11} }^{2} + { \sqrt{7} }^{2} - 2 \times \sqrt{11} \times \sqrt{7} }{11 - 7} \\ \frac{11 + 7 - 2 \sqrt{77} }{3} \\ \frac{17 - 2 \sqrt{77} }{3}
is the answer

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Hope it helps!!! :)

DaIncredible: bro i guess 11 - 7 = 4
DaIncredible: i might be wrong but please lemme know if im wrong
Answered by DaIncredible
13
Hey friend,
Here is the answer you were looking for:

(Solution in the image attached)


Hope this helps!!!

If you have any doubt regarding my answer, please ask in comment section or you can also inbox me.

@Mahak24

Thanks...
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