Question

root 125 - 3,under root 6 + root 294 -2under root 1/6 ​

Answer 1

$= > \sqrt{125} - 3 \sqrt{6} + \sqrt{294} - 2 \sqrt{ \frac{1}{6} } \\ = > 5 \sqrt{5} - 3 \sqrt{6} + 7 \sqrt{6} - 2 \sqrt{ \frac{1}{6} } \\ = > 5 \sqrt{5} + 4 \sqrt{6} - 2 \sqrt{ \frac{1}{6} }$