Question

[root 125 y^2 + root 25 y^4] ÷ 5 y^2​

Answer 1

Step-by-step explanation:

$\sqrt{125} {y}^{2} + \sqrt{25} {y}^{4} = 5 \sqrt{5} {y}^{2} + 5 {y}^{4} \\taking \: 5 {y}^{2} as \: common \: \\ = 5 {y}^{2} ( \sqrt{5} + {y}^{2} ) \\ \\ = \frac{5 {y}^{2}( \sqrt{5} + {y}^{2} ) }{5 {y}^{2} } \\ = ( \sqrt{5 + {y}^{2}) }$

here is your answer !!!

(hope it helps you )

mark as brainliest if you are satisfied!!!

:)