Math, asked by Ambitious1234567, 7 months ago

root 128 + root 320​

Answers

Answered by shivnisha474
1

Answer:

Explanation:

Simplify:

128

=

16

×

8

4

×

4

×

2

=

8

2

.

32

=

16

×

2

=

4

2

8

2

+

4

2

=

12

2

Answer link

AltairSafir

May 2, 2018

128

+

32

=

2

12

Explanation:

128

+

32

Write both numbers as a product of prime numbers.

(unique factorisation ).

For example:

my pic

my pic

128

=

2

64

=

2

2

32

32

=

2

16

=

2

2

8

=

2

2

2

4

=

2

5

=

2

4

2

128

+

32

=

2

2

32

+

32

=

=

2

2

32

+

32

=

2

32

+

32

=

=

3

32

=

3

2

4

2

=

3

2

4

2

=

3

2

2

2

=

=

3

4

2

=

12

2

Answer link

Tony B

May 2, 2018

12

2

Explanation:

Given:

128

+

32

You are looking for squared values that you can 'extract' from the roots.

If you are ever not sure do a quick sketch of a prime factor tree to help:

Tony B

Tony B

128

+

32

2

2

×

2

2

×

2

2

×

2

+

2

2

×

2

2

×

2

ddddd

8

2

dddddd

+

dddd

4

2

dddd

=

d

12

2

Answer link

Answered by muskanperween225
1

Step-by-step explanation:

 \sqrt{128}  +  \sqrt{320}

 =  \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2}  +  \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5}

 = 2 \times 2 \times 2 \sqrt{2}  + 2 \times 2 \times 2 \sqrt{5}

 = 8 \sqrt{2}  + 8 \sqrt{5}

 = 8( \sqrt{2}  +  \sqrt{5} )

Similar questions