Question

root 128 + root 8
pls answer this ​

Answer 1

Answer:

$\sqrt{128} + \sqrt{8} \\ = \sqrt{64 \times 2} + \sqrt{4 \times 2} \\ = \sqrt{ {8}^{2} \times 2 } + \sqrt{ {2}^{2} \times 2 } \\ = 8 \sqrt{2} + 2 \sqrt{2} \\ = \underline{ \underline{ 10 \sqrt{2} }}$