Root 13 minus a root 10 is equals to root 8 + root 5 in that find the value of a
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√[√13-a√10] = √8+√5
√13-a√10 = 8+5+2(√8)(√5)
√13-a√10 = 13+2√40
√13-a√10 = 13+4√10
-a√10 = 13+4√10-√13
a = -(13+4√10-√13)/√10
√13-a√10 = 8+5+2(√8)(√5)
√13-a√10 = 13+2√40
√13-a√10 = 13+4√10
-a√10 = 13+4√10-√13
a = -(13+4√10-√13)/√10
Hiteshbehera74:
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there is a whole root over root 13 a root-10
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