Question

root 147 + root 112 - root 75​

Answer 1

Step-by-step explanation:

$\sqrt{147} = \sqrt{ 3 \times 7 \times 7} = 7 \sqrt{3}$

$\sqrt{112} = \sqrt{2 \times 2 \times 2 \times 2 \times 7} \\ = 4 \sqrt{7}$

$\sqrt{75} = \sqrt{3 \times 5 \times 5} \\ 5 \sqrt{3}$

$now \\ \sqrt{147} + \sqrt{112} - \sqrt{75} \\ \\ = 7 \sqrt{3} + 4 \sqrt{7} - 5 \sqrt{3} \\ \\ = (7 \sqrt{3} - 5 \sqrt{3} ) + 4 \sqrt{7} \\ \\ = 2 \sqrt{3} + 4 \sqrt{7}$

Required Ans

Answer 2

$\huge\bf\underline{\color{red}{Question}}$

root 147 + root 112 - root 75

$\huge\bf\underline{\color{red}{Answer}}$

$\sqrt{147}+\sqrt{27}-\sqrt{75}=\sqrt{3×7²}+\sqrt{3²×3}-\sqrt{3×5²}$

=$(7+3-5)\sqrt{3}=5\sqrt{3}$