Question

root 2 + 1 by root 2 - 1 - root 2 - 1 by root 2 + 1 equal to a + b root 2 . it is urgent please give the correct answer ​

Answer 1

Answer:

$a = 0 \\ b \sqrt{2 } = 4$

Step-by-step explanation:

$\frac{ \sqrt{2} + 1 }{ \sqrt{2} - 1 } - \frac{ \sqrt{2} - 1}{ \sqrt{2} + 1 }$

$\frac{ \sqrt{2} + 1 \times \sqrt{2} + 1 - \sqrt{2} - 1 \times \sqrt{2} - 1} { \sqrt{2 } - 1 \times \sqrt{2} + 1 }$

$\frac{2 + 1 + 2 \sqrt{2} - (2 + 1 - 2 \sqrt{2)} }{2 - 1}$

$\frac{3 + 2 \sqrt{2} - 3 + 2 \sqrt{2} }{1}$

$4 \sqrt{2}$

So,

$b \sqrt{2 } = 4$

a=0

I hope you will understand

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