Question

Root 2 + 1 by root 2 ka whole square barabar

Answer 1

Answer:

$( \frac{ \sqrt{2 + 1} }{ \sqrt{2} } ) ^{2}$

Firstly Rationalising

• $\frac{ \sqrt{2 + 1 } }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} }$
• $\frac{ \sqrt{2( \sqrt{2 + 1)} } }{ (\sqrt{2) ^{2} } }$
• $\frac{2 + \sqrt{2} }{2}$
• $now. \\ ( \frac{2 + \sqrt{2} }{ 2} ) ^{2}$
• $\frac{4 + 2}{4}$
• $\frac{6}{4} = \frac{3}{2}$
• $\frac{3}{2} \: ans$
• Here is your answer