Question

root 2-1 /root 2 +1​

Answer 1

$\huge\boxed{\sf{ANSWER!!!!}}$

$= > \frac{ \sqrt{2 } - 1 }{ \sqrt{2} + 1}$

$= > \frac{ \sqrt{2 } - 1 }{ \sqrt{2} + 1} \times \frac{ \sqrt{2 } - 1 }{ \sqrt{2} - 1}$

$= > \frac{ {(\sqrt{2} - 1)}^{2} \: }{2 - 1}$

USE IDENTITY

${(x - y) }^{2}$

$= > { \sqrt{2} }^{2} + {1}^{2} + 2 \times \sqrt{2} \times 1$

$= > 2 + 1 + 2 \sqrt{2} \\ \\ = > 3 + 2 \sqrt{2}$

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