root 2 + 1 root 2 - 1 - 2 - 12 + 1 is equal to a + root 2 find the value of a and b
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Given Find a and b if root 2 +1 /root 2-1 -root2-1/root 2+1=a+toot2b
√2 + 1 / √2 - 1 - √2 - 1 / √2 + 1 = a + √b
Taking lcm we get
(√2 + 1)^2 - (√2 - 1)^2 /(√2 -1)(√2 + 1)
(√2)^2 + 1 + 2√2 - ((√2)^2 + 1 - 2√2) / 2 - 1
2 + 1 + 2√2 - (2 + 1 - 2√2)
a + √2 b = 4√2
√2 b = 4√2
b = 4, a = 0
So a = 0, b = 4
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