Question

root 2, 3 root 2, 5 root 2, which is 18th term of ap​

Answer 1

hope it help.........

Answer 2

Given:-

• AP = $\sf{ \sqrt{2} , 3 \sqrt{2} , 5 \sqrt{2}....... \sf a_n}$

To find:-

• $\sf a_{18} = ?$

Solution:-

• First term (a) = 2

• Commom difference (d) = $\sf{3 \sqrt{2} - \sqrt{2} = \sqrt{2}}$

$\bold{\underline{\underline{\boxed{\sf{\purple{\dag \; \sf a_{18} = a + 17d}}}}}}$

★ Putting the given values:-

$\implies \sf{ \sf a_{18} = \sqrt{2} + 17 \times 2 \sqrt{2}}$

$\implies \sf{ \sf a_{18} = \sqrt{2} + 34 \sqrt{2}}$

$\implies \bold{\underline{\underline{\boxed{\sf{\pink{\dag \; \sf a_{18} = 35 \sqrt{2}}}}}}}$

$\underline {\rule{261}{2}}$