Question

Root 2 by root 6 -root 2 -root 3 by root 6 +root 2

Answer 1

{√2/(√6-√2)} - {√3/(√6+√2)}

= [{√2(√6+√2)}-{√3(√6-√2)}]/(6-2)

= [√12+2-√18+√6]/4

= (√12)/4 + 2/4 - (√18)/4 + (√6)/4

= √3/2 + 1/2 - (3/2√2) + √6/4

Hope it's helpful to you.