root 2 Cos pi by 4 minus A is equals to Cos A + sin a prove that
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Proof:
Now, L.H.S. = √2 cos(π/4 - A)
= √2 [ cos(π/4) cosA + sin(π/4) cosA ]
= √2 [ 1/√2 * cosA + 1/√2 * cosA ]
= √2 / √2 ( cosA + sinA)
= cosA + sinA = R.H.S.
Hence, proved.
Trigonometric rules:
1. sin(A + B) = sinA cosB + cosA sinB
2. sin(A - B) = sinA cosB - cosA sinB
3. cos(A + B) = cosA cosB - sinA sinB
4. cos(A - B) = cosA cosB + sinA sinB
5. sin(π/4) = cos(π/4) = 1/√2
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