Question

(Root 2+i)×(1-root2i)

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

($\sqrt{2 + i}$ )×( $1- \sqrt{2i}$)

i = $\sqrt{-1}$

$\sqrt{2 + i - 2i - (+ \sqrt{2i} )}i$

$\sqrt{2+i-2i+\sqrt{2} }$

$-i+2\sqrt{2}$

∴$2\sqrt{2}$ -$i$

$-i^{2} = -1\\\\- (-\sqrt{2}) \\\\= + \sqrt{2}$

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