Question

root 2 + root 3/ 3 root 2 - 2 root 3 = a- b root 6

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\frac{ \sqrt{2} + \sqrt{3} }{3 \sqrt{2 } - 2 \sqrt{3} } = a - b \sqrt{6}$

$\sqrt{2} + \sqrt{3} = 3 \sqrt{2} - 2 \sqrt{3} (a - b \sqrt{6} )$

$\sqrt{2} + \sqrt{3} = 3 \sqrt{2}a - 3b \sqrt{12} - -2 \sqrt{3} a + 2b \sqrt{18}$