Question

Root 2+root 3/3root2-2root3=2-b root 6

Answer 1

Step-by-step explanation:

Hi ,

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]= [12+5√6]/[18-12]

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]= [12+5√6]/[18-12]= ( 12 + 5√6 )/6

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]= [12+5√6]/[18-12]= ( 12 + 5√6 )/6= 12/6 + 5√6/6

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]= [12+5√6]/[18-12]= ( 12 + 5√6 )/6= 12/6 + 5√6/6= 2 + (5/6)√6 ---( 1 )

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]= [12+5√6]/[18-12]= ( 12 + 5√6 )/6= 12/6 + 5√6/6= 2 + (5/6)√6 ---( 1 )= a + b√6-------( 2 )

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]= [12+5√6]/[18-12]= ( 12 + 5√6 )/6= 12/6 + 5√6/6= 2 + (5/6)√6 ---( 1 )= a + b√6-------( 2 )Compare ( 1 ) and ( 2 ) , we get

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]= [12+5√6]/[18-12]= ( 12 + 5√6 )/6= 12/6 + 5√6/6= 2 + (5/6)√6 ---( 1 )= a + b√6-------( 2 )Compare ( 1 ) and ( 2 ) , we geta = 2 , b = 5/6

Hi ,LHS = ( √2 + √3 )/(3√2-2√3)= [(√2+√3)(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]=[6+2√6+3√6+6]/[(3√2)²-(2√3)²]= [12+5√6]/[18-12]= ( 12 + 5√6 )/6= 12/6 + 5√6/6= 2 + (5/6)√6 ---( 1 )= a + b√6-------( 2 )Compare ( 1 ) and ( 2 ) , we geta = 2 , b = 5/6I hope this helps you.

Answer 2

refer the attachment given above!!