root 2+root 3 ÷ root 2 _ root 3 =a+b root 6
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Answered by
9
HELLO DEAR,
(√2+√3) / (√2-√3)
=> [(√2+√3)×(√2+√3)]/[(√2-√3)(√2+√3)]
=> [(4+3+2√6)/(4-3)]
=> (7+2√6)
Compare it with R.H.S
we get,
A =7 and B=2
I HOPE ITS HELP YOU DEAR,
THANKS
(√2+√3) / (√2-√3)
=> [(√2+√3)×(√2+√3)]/[(√2-√3)(√2+√3)]
=> [(4+3+2√6)/(4-3)]
=> (7+2√6)
Compare it with R.H.S
we get,
A =7 and B=2
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
8
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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