Question

root 2+ root 3 / root 3 - root 2=

Answer 1

Answer:

Step by step explanation

Step-by-step explanation:

$rationalise \: the \: denominator \\ \sqrt{3 } - \sqrt{2} \times \sqrt{3} + \sqrt{2 }$

.

(a-b)×(a+b)=a²-b²

$\sqrt{3 {}^{2} } - \sqrt{2 {}^{2} }$

3-2

=1

$\sqrt{2} ( \sqrt{3} + \sqrt{2} ) + \sqrt{3} ( \sqrt{3} + \sqrt{2} )$

$( \sqrt{6} + 2) + (3 + \sqrt{6} )$

$2 \sqrt{6} + 5$

Answer 2

Answer:

I don't know question is answer sorry

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