Math, asked by nidhiparashar22392, 8 months ago

root 2 upon root 5 + root 3 upon root 2 (2 root 2 + root 3)​

Answers

Answered by saradayanamandra5256
6

Step-by-step explanation:

2/root5+root3 × root5- root3/root 5- root 3=2root5-2root3/2

=>2 [root5 -root3]/2

=> [root5-root3]

= 1/ root3+ root2 × root3-root2/root3-root2= root3-root2/1

=>[root3- root2]

3/root5+root2 × root5-root2/root5-root2

=3root5-3root2/3 => 3(root5- root2)/3

=>[ root5-root2]

now substitute the values

=> root5-root3+root3-root2-( root5-root2)

=> cut all the common roots on the following

=0

please mark me as brainliest

Answered by pragatiairara820
3

Answer:

0 is the answer

Step-by-step explanation:

hope it helps you

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