root 2 x + root 3y = 0 root 3x - root 8y =0 find value of x and y by substitution method
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he given pair of equations are: √2x – √3y = 0…………
(i) √3x − √8y = 0…………
(ii) From equation
(i) x = √(3/2)y ……………..
(iii) Substituting this value in equation
(ii) we obtain √3x − √8y = 0 ⇒ √3(√(3/2)y) − √8y = 0 ⇒ (3/√2)y – √8y = 0 ⇒ 3y – 4y = 0 ⇒ y = 0 Now, substituting y in equation (iii) we obtain ⇒ x = 0 Thus, the value of x and y obtained are 0 and 0 respectively.Read more on Sarthaks.com - https://www.sarthaks.com/625460/solve-the-following-system-of-equations-2x-3y-0-3x-8y-0
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