Question

root 2 X square + 7 x + 5 root 2 is equals to zero

Answer 1

Answer:

x1= 5root2/2. x2= root2

Answer 2

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 \\ \sqrt{2} {x}^{2} + 5x + 2x + 5 \sqrt{2} = 0 \\ x( \sqrt{2} x + 5) + \sqrt{2} ( \sqrt{2} x + 5) = 0 \\ x + \sqrt{2} = 0 \\ x = - \sqrt{2} \\ \sqrt{2} x + 5 = 0 \\ x = - 5 \div \sqrt{2}$

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