Math, asked by himanshu4024, 1 year ago

Root 2 x square + 7x + 5root 2 =0

Answers

Answered by adarsh77179
7
give me brainiest if It helped

√2 x2 + 7x + 5√2 = 0



√2 x2 + 2x+ 5x + 5√2 = 0

√2x (x+√2 ) + 5 ( x + √2 ) = 0

( √2 + x ) ( √2 x + 5 ) =0

therefore x = -√2 , x = - 5 / √2
Answered by nazsah
1

rt2x^2 + 7x +5rt2 = (rt2x^2 + 2x) + (5x + 5rt2)
= rt2x ( 1x + rt2 ) + 5 (1x + rt2)
= (rt2x + 5) ( 1x + rt2) =0
Implies (rt2x + 5) =0 or (1x + rt2)=0
x=-5/rt2 or x=-rt2
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