Question

root 243÷
$\sqrt{243} \div \sqrt{363}$​

Answer 1

Answer:

$\sqrt{243} \div \sqrt{363}$

$\sqrt{3 \times 3 \times 3 \times 3 \times 3 } \div \sqrt{3 \times 11 \times 11}$

$9 \sqrt{3} \div 11 \sqrt{3}$

$\frac{9 \sqrt{3} }{11 \sqrt{3} }$

$\frac{9}{11}$